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Rates of reaction: graphs

Read gas-volume graphs, calculate mean rates and use tangent gradients where required.

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The chemistry

A gas syringe can measure the volume of gas collected as a reaction proceeds. Plot gas volume on the vertical axis and time on the horizontal axis. Check the units before calculating a gradient.

A mean rate over an interval is the change in volume divided by the time interval. For example, a rise of 42 cm³ over 30 s gives 1.4 cm³/s. The volume already in the syringe is not a rate.

At any point on a curved volume–time graph, the gradient of a tangent shows how quickly the volume is changing at that instant. Use two widely separated points on the drawn tangent; they need not be observed data points on the curve.

On the invented gas-collection curves, the graph rises steeply at first and then levels off. The falling gradient means less gas is produced per second as the run progresses. A flat line means the measured volume is no longer increasing.

AQA Foundation interprets tangents but does not require the numerical gradient of a tangent. AQA Higher does. Pearson Edexcel includes graph gradients in its rates requirements without a Higher-only restriction.

Worked example

If the syringe reading changes from 15 cm³ at 20 s to 43 cm³ at 40 s, the mean rate over that interval is (43 − 15) ÷ (40 − 20) = 1.4 cm³/s.

Suppose two points on a tangent are (10 s, 20 cm³) and (30 s, 52 cm³). The gradient is (52 − 20) ÷ (30 − 10) = 1.6 cm³/s. This is the instantaneous rate at the time where that tangent touches the original curve.

Specification references

AQA GCSE Chemistry 8462 4.6.1.1–4.6.1.3 and required practical 5; Pearson Edexcel 1CH0 Issue 4 7.1–7.5. Select your course to see which questions apply.

Read the graph and interpret the data

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A student divides the gas volume at 40 seconds by 40 and says this is the rate exactly at 40 seconds. Assess that answer.

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  • Identify the calculation as a mean over 0–40 seconds.
  • Explain that rate at a time comes from the gradient of a tangent.
  • Say why an average over an interval can differ from a tangent gradient.

Example answer

Dividing the volume at 40 seconds by 40 seconds gives the mean rate from the start. It is not the rate at precisely 40 seconds. The rate at that instant is the slope of a tangent to the curve at 40 seconds, which is smaller here because the curve is flattening.

An answer to improve

The volume has gone up, so the rate at 40 seconds must be increasing.

Improve your answer

Draw the tangent at the time asked for. Use two well-separated points on that straight line to calculate its gradient.

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